According to ABC News, the Golden State Warriors currently have a 43 percent chance of actually attaining 73 wins this season. On the flip side, they do have a 68 percent chance of getting at least 72 wins, though. So, there’s a, basically, two-in-three chance that the team at least ties the 1995-96 Chicago Bulls for most wins in a season.
The following graphic is taken from the ABC News article and is courtesy of ESPN:
If you want to put it into fun terms, the Warriors have nearly the same chance of winning 72 games this season as DeAndre Jordan does of making a shot. Jordan makes 69 percent of his field goal attempts, and Golden State has a 68 percent chance of winning 72 games. See? Fun! But let’s keep it going.
The team has the same chance of winning 73 games this season as the Cleveland Cavaliers’ Matthew Dellavedova does of making a three-pointer this season — 43 percent. They have a 93 percent chance of being the top seed in the Western Conference, which is what Jamal Crawford shot from the free throw line in the 2011-12 season with Portland.
They have a 45 percent chance of reaching the NBA finals, which is almost exactly what Stephen Curry shoots from beyond the arc (46 percent) this season. And they have a 39 percent chance of winning it all, which is the same percentage “Skinny” Kyle Lowry is shooting from deep.
Essentially, the Warriors have a shooter’s chance at all of this stuff. And not just average shooters, but rather good shooters. So it’s fun to look at this way. The team has a 43 percent chance of reaching 73 wins, and the Andre Iguodala injury makes this tougher, but they do seem poised to do it.